//Chapter 6:Induction Motor Drives //Example 8 clc; //Variable Initialization //Ratings of the delta connected Induction motor f=50 // frequency in HZ Vl=400 // line voltage in V P=4 // number of poles Pm=2.8*1000 // rated mechanical power developed in W N=1370 // rated speed in rpm //Parameters referred to the stator Xr_=5 // rotor winding reactance in ohm Xs=Xr_ // stator winding reactance in ohm Rr_=5 // resistance of the rotor windings in ohm Rs=2 // resistance of the stator windings in ohm Xm=80 // no load reactance in ohm //Solution Ns=120*f/P //synchronous speed in rpm Wms=2*%pi*Ns/60 //synchronous speed in rad/s s=(Ns-N)/Ns //full load slip x=(Rs+Rr_/s)**2+(Xs+Xr_)**2 //total impedance T=(3/Wms)*(Vl**2*Rr_/s)/x //full load torque Tl=T K=Tl/(1-s)**2 //since Tl=K*(1-s)**2 //(i) When the motor is running at 1200 rpm N1=1200 //speed in rpm s1=(Ns-N1)/Ns //slip at the given speed N1 Tl=K*(1-s1)**2 //torque at the given speed N1 y=(Rs+Rr_/s1)**2+(Xs+Xr_)**2 //total impedance a=Tl*(Wms/3)*y*(s1/Rr_) //Since T=(3/Wms)*(Vl**2*Rr_/s)/x and a=V**2 V=sqrt(a) //required voltage at the given speed N1 Ir_=V/((Rs+Rr_/s1)+%i*(Xs+Xr_))//rotor current Im=V/(%i*Xm) //magnetizing current Is=Ir_+Im //total current Il=abs(Is)*sqrt(3) //line current //(ii)When the terminal voltage is 300 V V1=300 //terminal voltage in V x=(Rs+Rr_)**2+(Xs+Xr_)**2 T=(3/Wms)*(V1**2*Rr_)/x //Now we have to solve for the value of slip 's' from the given equation 104s**4- 188s**3 + 89s**2 - 179s + 25=0" coeff = [104,-188,89,-179,25] //coeffcient of the polynomial equation s=[] s=roots(coeff) //roots of the polynomial equation T=K*(1-real(s(4)))**2 //torque at the given terminal voltage of 300 V N=Ns*(1-real(s(4))) //speed at the given terminal voltage of 300 V Ir_=V1/((Rs+Rr_/real(s(4)))+%i*(Xs+Xr_))//rotor current Im=V1/(%i*Xm) //magnetizing current Is=Ir_+Im //total current Il1=abs(Is)*sqrt(3) //line current //Results mprintf("(i)Required torque is Tl:%.1f N-m",Tl) mprintf("\nRequired motor terminal voltage is V: %.1f V",V) mprintf("\nRequired line current is Il:%.2f A",Il) mprintf("\n(ii)The roots of the polynomial equation are s1:%.3f s2:%.3f s3:%.3f s4:%.3f",real(s(1)),real(s(2)),real(s(3)),real(s(4))) mprintf("\nHence Only s4: %.3f is valid",real(s(4))) mprintf("\nRequired torque is Tl:%.2f N-m",T) mprintf("\nRequired speed is N:%.1f rpm",N) mprintf("\nRequired line current is Il:%.2f A",Il1)