//Chapter 6:Induction Motor Drives //Example 7 clc; //Variable Initialization //Ratings of the Star connected Induction motor f=50 // frequency in HZ Vl=2200 // line voltage in V P=6 // number of poles //Parameters referred to the stator Xr_=0.5 // rotor winding reactance in ohm Xs=Xr_ // stator winding reactance in ohm Rr_=0.12 // resistance of the rotor windings in ohm Rs=0.075 // resistance of the stator windings in ohm J=100 // combine inertia of motor and load in kg-m2 //Solution //(i) During starting of the motor Sm=Rr_/sqrt(Rs**2+(Xs+Xr_)**2) //slip at maximum torque Wms=4*%pi*f/P //angular frequency x=Rs+sqrt(Rs**2+(Xs+Xr_)**2) Tmax=(3/2/Wms)*(Vl/sqrt(3))**2/x //maximum torque tm=J*Wms/Tmax //mechanical time constant of the motor ts=tm*(1/4/Sm+1.5*Sm) //time taken during starting Es=1/2*J*Wms**2*(1+Rs/Rr_) //energy disspated during starting //(ii) When the motor is stopped by plugging method tb=tm*(0.345*Sm+0.75/Sm) //time required to stop by plugging Eb=3/2*J*Wms**2*(1+Rs/Rr_) //energy disspated during braking //(iii)Required resistance to be inserted during plugging tb1=1.027*tm //minimum value of stopping time during braking x=1.47*(Xs+Xr_) //x=Rr_+Re Re=x-Rr_ //Re is the required external resistance to be connected Ee=3/2*J*Wms**2*(Re/(Re+Rr_)) //energy disspated in the external resistor Eb1=Eb-Ee //total energy disspated during braking //Results mprintf("(i)Time taken during starting is ts:%.4f s",ts) mprintf(" \nEnergy dissipated during starting is Es:%d kilo-watt-sec",Es/1000) mprintf("\n\n(ii)Time taken to stop by plugging is tb:%.2f s",tb) mprintf(" \nEnergy dissipated during braking is Eb:%d kilo-watt-sec",Eb/1000) mprintf("\n\n(iii)Minimum Time taken to stop by plugging is tb:%.2f s",tb1) mprintf(" \nRequired external resistance to be connected is Re:%.2f ohm",Re) mprintf(" \nTotal Energy dissipated during braking is Eb:%.2f kilo-watt-sec",Eb1/1000)