//Chapter 3: Thermodynamic and Chemical Equilibrium //Problem: 13 clc; //Declaration of Constants l_v = 101 //in cal /g, Latent headt of vap. mwt = 78 // molecular weight of benzene //Declaration of Variable m = 2 Tb = 80.2 // C, boiling point of benzene // Solution Tb = Tb + 273 // K d_h = l_v * mwt d_s = d_h / Tb d_g = d_h - Tb * d_s mprintf("d_s = %.2f cal / K\n",d_s) mprintf(" d_g = d_a = %d", d_g)