// Example 3.5 // Determine (a) Rated high side current of each transformer (b) Percent of the // total bank-current drawn by each transformer (c) Maximum load that can be // handled by the bank without overloading by one of the transformer // Page No. 107 clc; clear; close; // Given data SA=75000; // Transformer A rating SB=200000; // Transformer B rating VHSA=2400; // Voltage at the high side of transformer A VHSB=2400; // Voltage at the high side of transformer B RPUA=1.64; // Percent resistance of transformer A XPUA=3.16; // Percent reactance of transformer A RPUB=1.10; // Percent resistance of transformer B XPUB=4.03; // Percent reactance of transformer B // (a) Rated high side current of each transformer IArated=SA/VHSA; // High side rated current transformer A IBrated=SB/VHSB; // High side rated current transformer B // (b) Percent of the total bank-current drawn by each transformer ZAper=RPUA+%i*XPUA; // Percent impadance for transformer A // Complex to Polar form... ZAper_Mag=sqrt(real(ZAper)^2+imag(ZAper)^2); // Magnitude part ZAper_Ang=atan(imag(ZAper),real(ZAper))*180/%pi; // Angle part
 ZBper=RPUB+%i*XPUB; // Percent impadance for transformer B // Complex to Polar form... ZBper_Mag=sqrt(real(ZBper)^2+imag(ZBper)^2); // Magnitude part ZBper_Ang=atan(imag(ZBper),real(ZBper))*180/%pi; // Angle part
 ZAbase=VHSA/IArated; // Base impedance of transformer A ZBbase=VHSB/IBrated; // Base impedance of transformer A ZeqA_Mag=ZAbase*ZAper_Mag/100; // Magnitude of equivalent impedance A ZeqA_Ang=ZAper_Ang; // Angle of equivalent impedance A ZeqB_Mag=ZBbase*ZBper_Mag/100; // Magnitude of equivalent impedance B ZeqB_Ang=ZBper_Ang; // Angle of equivalent impedance B YeqA_Mag=1/ZeqA_Mag; // Magnitude of equivalent admittance A YeqA_Ang=0-ZeqA_Ang; // Angle of equivalent admittance A // Polar to Complex form YeqA_R=YeqA_Mag*cos(-YeqA_Ang*%pi/180); // Real part of complex number YeqA_I=YeqA_Mag*sin(YeqA_Ang*%pi/180); //Imaginary part of complex number YeqB_Mag=1/ZeqB_Mag; // Magnitude of equivalent admittance B YeqB_Ang=0-ZeqB_Ang; // Angle of equivalent admittance B // Polar to Complex form YeqB_R=YeqB_Mag*cos(-YeqB_Ang*%pi/180); // Real part of complex number YeqB_I=YeqB_Mag*sin(YeqB_Ang*%pi/180); //Imaginary part of complex number YP=(YeqA_R - %i* YeqA_I)+(YeqB_R - %i* YeqB_I); // Parallel admittance // Complex to Polar form... YP_Mag=sqrt(real(YP)^2+imag(YP)^2); // Magnitude part YP_Ang=atan(imag(YP),real(YP))*180/%pi; // Angle part
 IA=YeqA_Mag/YP_Mag; // Transformer A load IB=YeqB_Mag/YP_Mag; // Transformer A load IA=IA*100; IB=IB*100; // (c) Maximum load that can be handled by the bank without overloading by // one of the transformer Ibank=IArated/0.307; // Display result on command window printf("\n Rated high side current of transformer A = %0.2f A ",IArated); printf("\n Rated high side current of transformer B = %0.3f A ",IBrated); printf("\n Percent of total bank current drawn by transformer A = %0.0f Percent ",IA); printf("\n Percent of total bank current drawn by transformer B = %0.0f Percent ",IB); printf("\n Maximum load that can be handled by the bank = %0.2f A ", Ibank);