clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 2 : AC Circuits // Chapter 12 : Three Phase Circuit // Example 12 - 4 clear; clc; close; // // Given data Vab_mag = 330.0000; Vab_angle = 0.0000; Zdelta = complex(20,-15); // // Calculations Phase Voltage (VAB) VAB_mag = Vab_mag VAB_angle = Vab_angle // Calculatioan Phase Current AB I_AB_mag = VAB_mag/norm(Zdelta) Zdelta_real = real(Zdelta) Zdelta_imag = imag(Zdelta) Zdelta_angle = atand(Zdelta_imag,Zdelta_real) I_AB_angle = Vab_angle - Zdelta_angle // Calculations Phase Current BC I_BC_mag = I_AB_mag; I_BC_angle = -120.0000 + I_AB_angle; // Calculations Phase Current CA I_CA_mag = I_AB_mag; I_CA_angle = 120.0000 + I_AB_angle; // Calculations Line Current a I_a_mag = (3)^0.5 * I_AB_mag; I_a_angle = -30.0000 + I_AB_angle; // Calculations Line Current b I_b_mag = I_a_mag; I_b_angle = -120.0000 + I_a_angle; // Calculations Line Current c I_c_mag = I_a_mag; I_c_angle = 120.0000 + I_a_angle; // disp("Example 12-4 Solution : "); printf(" \n I_AB_mag = Magnitude of Phase Currents AB = %.3f A",I_AB_mag) printf(" \n I_AB_angle = Angle of Phase Current AB = %.3f Degree",I_AB_angle) printf(" \n I_BC_mag = Magnitude of Phase Currents BC = %.3f A",I_BC_mag) printf(" \n I_BC_angle = Angle of Phase Current BC = %.3f Degree",I_BC_angle) printf(" \n I_CA_mag = Magnitude of Phase Currents CA = %.3f A",I_CA_mag) printf(" \n I_CA_angle = Angle of Phase Current CA = %.3f Degree",I_CA_angle) printf(" \n I_a_mag = Magnitude of Line Currents a = %.3f A",I_a_mag) printf(" \n I_a_angle = Angle of Line Current a = %.3f Degree",I_a_angle) printf(" \n I_b_mag = Magnitude of Line Current b = %.3f A",I_b_mag) printf(" \n I_b_angle = Angle of Line Current b = %.3f Degree",I_b_angle) printf(" \n I_c_mag = Magnitude of Line Currents c = %.3f A",I_c_mag) printf(" \n I_c_angle = Angle of Line Current c = %.3f Degree",I_c_angle)