//Chapter 3, Exmaple 6, page 105
//Determine mean free path 
clc
clear
//(a) Mean free path
na = %e^-1
//(b) 5 times mean free path
nb = %e^-5
printf("\n Mean free path = %f*n0 ",na)
printf("\n 5 times mean free path = %f*n0 ",nb)

//Answer may vary due to round of error