//scilab 5.4.1 clear; clc; printf("\t\t\tProblem Number 5.35\n\n\n"); // Chapter 5 : Properties Of Liquids And Gases // Problem 5.35 (page no. 218) // Solution //As already noted,h1=h2 for this process.On the Mollier chart,h2 is found to be 1170 Btu/lbm at 14.7 psia and 250 F.Proceeding to the left on the chart,the constant-enthalpy value of 1170 Btu/lbm to 150 psia yields a moisture of 3% or a quality of 97%. //If we use the tables to obtain the solution to this problem,we would first obtain h2 from the superheated vapor tables as 1168.8 Btu/lbm.Because hx=hf+(x*hfg),we obtain x as hx=1168.8; //Btu/lbm hf=330.75; //Btu/lbm //values of 150 psia hfg=864.2; //Btulbm //values of 150 psia x=(hx-hf)/hfg; //Quality printf("Moisture in the steam flowing in the pipe is %f percent\n",(1-x)*100); printf("or quality of the steam is %f percent\n",x*100); //very often,it is necessary to perform multiple interpolations if the tables are used,and the Mollier chart yields results within the rquired accuracy for most engineering problems and saves considerable time. //We can also use the computerised programs to solve this program.We first enter the 250F and 14.7 psia to obtain h of 1168.7 Btu/lbm.We then continue by entering h of 1168.7 Btu/lbm and p of 150 psia.The printout gives us x of 0.9699 or 97%.While the computer solution is quick and easy to use,you should still sketch out the problem on an h-s or T-s diagram to show the path of the process. // Saturation Properties //-------------------------- // T=250.00 degF // P=29.814 psia // z z1 zg // v(ft^3/lbm) 0.01700 13.830 // h(Btu/lbm) 218.62 1164.1 // s(Btu/lbm*F) 0.3678 1.7001 // u(Btu/lbm) 218.52 1087.8 //Thermo Properties //------------------------ // T= 250.00 degF // P= 14.700 psia // v= 28.417 ft^3/lbm // h= 1168.7 Btu/lbm // s= 1.7831 Btu/lbm*F // u= 1091.4 Btu/lbm // Saturation Properties //-------------------------- // T=340.06 degF // P=118.00 psia // z z1 zg // v(ft^3/lbm) 0.01787 3.7891 // h(Btu/lbm) 311.39 1190.7 // s(Btu/lbm*F) 0.4904 1.5899 // u(Btu/lbm) 311.00 1108.0 //Thermo Properties //------------------------ // T= 358.49 degF // P= 150.00 psia // v= 2.9248 ft^3/lbm // h= 1168.7 Btu/lbm // s= 1.5384 Btu/lbm*F // u= 1087.5 Btu/lbm // x= 0.9699 //Region:Saturated