// Exa 4.8
clc;clear;close;
// Given data
format('v',8)
n = 4;// number of bit
R = 1/(10^n);
disp(R,"Part (i) : The resolution is");
// There are 5 digit places in 4 1/2 digits, so
disp("Part (ii) : 11.87 would be displayed as 11.870")
Reading= 0.5573;
format('v',7)
disp(Reading,"Part (iii) : On 1 V range, 0.5573 will be displayed as : ")
format('v',6)
disp(Reading,"On 10 V range, 0.5573 will be displayed as : ")