//chapter 1
// eaxample 1.4
//page 26
printf("\n")
printf("given")
T1=25;T2=35;T3=45;
I0=30//nA
disp("I0(35)=I0*2^(T2-T1)/10")
//on solving
I0(35)=I0*2^((T2-T1)/10);
printf("current at 35c is %dnA\n",I0(35))
disp("I0(45)=I0*2^(T3-T1)/10")
//on solving
I0(45)=30*2^2;
printf("current at 45c is %dnA\n",I0(45))