//example 2.1 //calculate time required to cover 0.1 hectare area by tubewell clc; //Given Q=0.0108, //discharge through well y=0.075, //average depth of flow I=0.05, //average infiltration rate A=0.1, //area to cover t=(60*2.303*y*log10(Q/(Q-I*A)))/I, t=round(t); mprintf("Time required to cover given area=%f minutes.",t);