//Chapter-3,Example 3_5,Page 3-20 clc() //Given Data: u1=1.5 //R.I. of Core u2=1.45 //R.I.of Cladding del=(u1-u2)/u1 //Fractional Refractive index //Calculations: NA=u1*sqrt(2*del) //Formula to find NA theta0=asin(NA)*180/%pi //Acceptance angle thetac=asin(u2/u1)*180/%pi //Critical angle printf('Numerical Aperture of Fibre is =%.3f \n \n',NA) printf(' Acceptance angle of Fibre is =%.2f degrees \n \n',theta0) printf(' Critical angle of Fibre is =%.1f degrees \n',thetac)