clear all; clc; disp("Scilab Code Ex 12.16 : ") //Given: k = 45; //kN/m F = 3; //kN E = 200*10^6; //kPa l_ab = 3; //m l_ac = 1; //m l_cb = 2; //m I = 4.687*10^-6; //m^4 R_a = (F*l_cb)/(l_ab); R_b = F-R_a; //Calculations: nu_a = (R_a)/k; nu_b = (R_b)/k; nu_c1 = nu_b + (l_cb/l_ab)*(nu_a - nu_b); nu_c2 = ((F*l_ac*l_cb)*(l_ab^2 - l_ac^2 - l_cb^2))/(6*E*I*l_ab); nu_c = nu_c1 + nu_c2; nu_C = nu_c*1000; //Display: printf('\n\nThe vertical displacement of the force at C = %1.3f mm',nu_C); //----------------------------------------------------------------------END--------------------------------------------------------------------------------