//ANALOG AND DIGITAL COMMUNICATION //BY Dr.SANJAY SHARMA //CHAPTER 5 //ANGLE MODULATION clear all; clc; printf("EXAMPLE 5.47(PAGENO 264)"); //given f_m = 2*10^3//modulating frequency for first case delta_f1 = 5*10^3//frequency deviation for first case f_m1 = 1*10^3//modulating frequency for second case //beeta = (k_f*a_m)/(w_m) = delta_f/f_m //calculations beeta = delta_f1/f_m f_B1 = 2*(beeta + 1)*f_m//bandwidth for first case //beeta1 = (k_f*3*a_m)/(.5*w_m) = delta_f/f_m therefore beeta1 = 6*beeta delta_f2 = beeta1 * f_m1 //frequency deviation for second case f_B2 = 2*(beeta1 + 1)*f_m1//bandwidth for second case //results printf("\n\ni.Bandwidth for first case = %.2f Hz",f_B1); printf("\n\nii.a.Frequency deviation for second case =%.2f Hz",delta_f2); printf("\n\n b.Bandwidth for second case = %.2f Hz",f_B2);