// Example14.11 // Design a video amplifier of IC 1550 circuit clc; clear; close; Vcc = 12 ; // V Av = -10 ; Vagc = 0 ; // at bandwidth of 20 MHz hfe = 50 ; // forward emitter parameter rbb = 25 ; // ohm // base resistor Cs = 1*10^-12 ; // F // source capacitor Cl = 1*10^-12 ; // F // load capacitor Ie1 = 1*10^-3 ; // A // emitter current of Q1 f = 1000*10^6 ; // Hz Vt = 52*10^-3 ; Vt1 = 0.026 ; // When Vagc =0 the transistor Q2 is cut-off and the collector current of transistor Q2 flow through the transistor Q3 // i.e Ic1=Ie1=Ie3 Ie3 = 1*10^-3 ; // A // emitter current of Q3 Ic1 = 1*10^-3 ; // A // collector current of the transistor Q1 // it indicates that the emitter current of Q2 is zero Ie2 = 0 then the emitter resistor of Q2 is infinite re2 = %inf ; // emitter resistor of Q3 re3 = (Vt/Ie1); disp('The emitter resistor of Q3 is = '+string(re3)+' ohm '); // the trans conductance of transistor is gm = (Ie1/Vt1); disp('The trans conductance of transistor is = '+string(gm)+' A/V '); // the base emitter resistor rbe rbe = (hfe/gm); disp('The base emitter resistor rbe is = '+string(rbe)+' ohm '); // the emitter capacitor Ce Ce = (gm/(2*%pi*f)); disp('The emitter capacitor is = '+string(Ce)+' F '); // the voltage gain of video amplifier is // Av = (Vo/Vin) ; // Av = -((alpha3*gm)/(rbb*re3)*((1/rbb)+(1/rbe)+sCe)*((1/re2)+(1/re3)+sC3)*((1/Rl)+(s(Cs+Cl)))) // At Avgc = 0 i.e s=0 in the above Av equation alpha3 = 1 ; s = 0 ; Av =-10 ; Rl = -((alpha3*gm)/((rbb*re3)*(((1/rbb)+(1/rbe))*((1/re2)+(1/re3))*(Av)))); Rl = (1/Rl); disp('The value of resistance RL is = '+string(Rl)+' ohm '); // there are three poles present in the transfer function of video amplifier each pole generate one 3-db frequency Rl = 265 fa = 1/(2*%pi*Rl*(Cs)); disp('The pole frequency fa is = '+string(fa)+' Hz '); fb = 1/(2*%pi*Ce*((rbb*rbe)/(rbb+rbe))); disp('The pole frequency fb is = '+string(fb)+' Hz '); fc = 1/(2*%pi*Cs*re3); disp('The pole frequency fc is = '+string(fc)+' Hz '); disp(' Hence fa is a dominant pole frequency ');