// Examle 4.1

               // Reffer the diagram (4.2a)
               // Using Superpositon theorem

I=-0.5;                       // Source current
I1=I*(0.3/(0.1+0.3));         // When 0.5-A Current source is on { by voltage divider }

V=80*10^-3;                   // Voltage source
I2=(V/(0.1+0.3));             // When 80-mV voltage source is on { by ohm's law }

i=I1+I2;                      // Current in the circuit  { by Superpositon theorem }
disp(' Current in the circuit = '+string(i)+' Amp');





           //   p 105          4.1