//CHAPTER 1- D.C. CIRCUIT ANALYSIS AND NETWORK THEOREMS 
//Example 54

disp("CHAPTER 1");
disp("EXAMPLE 54");

//VARIABLE INITIALIZATION
v=5;                            //voltage source in Volts
r1=1;                           //LHS resistance in Ohms
r2=5;                           //in Ohms
r3=1;                           //in Ohms
r4=1;                           //RHS resistance in Ohms
I=10;                           //current source in Amperes

//SOLUTION

//on deactivating the current source, current I1 flows in the circuit
req1=r1+r3+r4;
I1=v/req1;
vab1=v-(I1*r1);                 //(I1*r1) is voltage drop across 1Ω resistance
I2=I/req1;
vab2=vab1+(I2*r1);              //(I2*r1) is voltage drop across 1Ω resistance
rth=r1+((r3*r4)/(r3+r4));
Ith=vab2/(rth+r2);
Rth=(6/5)+(3/4);
req2=10+2;
I3=9/12;
disp(sprintf("The value of the current is %f A",I3));

//END