//Chapter-12, Example 12.15, Page 530 //============================================================================= clc clear //INPUT DATA Tci=5;//Inlet temperature of water in degree C mc=4600;//Mass flow rate of water in kg/h mh=4000;//Mass flow rate of air in kg/h Thi=40;//Inlet temperature of air in degree C U=150;//Overall heat transfer coefficient in W/m^2.K A=25;//Area of heat exchanger in m^2 Cc=4180;//Specific heat of water in J/kg.K Ch=1010;//Specific heat of air in J/kg.K //CALCULATIONS C1=((mh*Ch)/3600);//Heat capacity of air in W/K C2=((mc*Cc)/3600);//Heat capacity of water in W/K Cmin=min(C1,C2);//Minimum value of heat capacity in W/K Cmax=max(C1,C2);//Maximum value of heat capacity in W/K r=(Cmin/Cmax);//Ratio of min and max heat capacity in W/K NTU=((U*A)/Cmin);//Number of heat transfer units e=0.92;//Effectiveness of heat exchanger from Fig. 12.18 on page no.526 Q=(e*Cmin*(Thi-Tci));//Heat transfer rate in W Tco=((Q/C2)+Tci);//Outlet temperature of water in degree C Tho=(Thi-(Q/C1));//Outlet temperature of air in degree C //OUTPUT mprintf('The exit temperature of water is %3.1f degree C \n The exit temperature of air is %3.1f degree C',Tco,Tho) //=================================END OF PROGRAM==============================