clear;
clc;

// Stoichiometry
// Chapter 4
// Material Balances involving Chemical Reaction


// Example 4.14
// Page 140
printf("Example 4.14, Page 140 \n \n");

// solution

// using equations of example 4.10

// soving 4.10 by linear model method
M = [1 0 0 0 0 0 0 0 0 0 0 0 0 0 0;0 1 0 0 0 0 0 0 0 0 1 1 1 1 2;0 0 1 0 0 0 0 0 0 0 .5 1.5 0 -.5 0;0 0 0 1 0 0 0 0 0 0 -1 -2 0 0 -1;0 0 0 0 1 0 0 0 0 0 -1 0 0 0 0;0 0 0 0 0 1 0 0 0 0 0 -1 0 0 0;0 0 0 0 0 0 1 0 0 0 0 0 -1 0 0;0 0 0 0 0 0 0 1 0 0 0 0 -2 0 0;0 0 0 0 0 0 0 0 0 0 0 0 0 -1 0;0 0 0 0 0 0 0 0 0 1 0 0 0 0 -1;0 0 0 0 0 0 0 0 0 0 1 1 1 1 2;0 0 0 0 0 0 0 0 0 0 .5 1.5 0 -.5 0;0 0 0 0 0 0 0 0 0 0 -1 -2 0 0 -1;0 0 0 0 0 0 0 0 0 0 0 0 0 1 0;0 0 0 0 0 0 0 0 0 0 0 0 0 0 2]
V = [1058.1;125;281.27;23.73;0;0;0;0;0;0;.99*125;.2437*281.27;-5.4756*23.73;.61875;1.98]
X = M\V
disp(X)