// 2.38 clc; b=0.02; t=0.004; I=(1/12)*b*t^3; F=25; l=0.25; E=200*10^9; x=(F*l^3)/(3*E*I); printf("deflection=%.2f m",x) DpF=x/F; Se=DpF*0.5*1000; Re=(10/1000)*(2/10); F_min=Re/Se; F_max=10/Se; printf("\nminimum force=%.2f N",F_min) printf("\nmaximum force=%.2f N",F_max)