//Example 5.3
 
//Page 256
 
k=7//from equation 5.14 on page 256
 
disp('Using the value of k')
 
disp('Using the value of k, the number of crosspoint determined are')
 
2*7*16

disp('The number of bits of memory can be determined are')
 
N=[2*7*128*4]+[7*128*8]+[7*128*7]

//Result
 
//The composite implementation complecity is 430 equivalent crosspoints.