//Example 9.32
clc
disp("For the given DAC,")
disp("  n = Number of bits = 8")
disp("(i) Resolution = 2^n = 2^8 = 256")
disp("i.e. the output voltage can have 256 different values including zero.")
disp("(ii)  V_0FS = Full scale output voltage")
disp("            = 2.55 V")
disp("Therefore,  Resolution = V_0FS / 2^n - 1 = 2.55 / 2^8 - 1 = 10mV / 1LSB")
disp("Thus an input change of 1LSB causes the output to change by 10mV")