// Electric Machinery and Transformers // Irving L kosow // Prentice Hall of India // 2nd editiom // Chapter 14: TRANSFORMERS // Example 14-29 clear; clc; close; // Clear the work space and console. // Given data // From diagram in fig.14-25a Z_pu_1 = %i*0.1 ; // p.u impedance MVA_2 = 80 ; // MVA rating os system 2 MVA_1 = 100 ; // MVA rating of Tr.s 1 and 2 V_2 = 30 ; // voltage in KV V_1 = 32 ; // voltage in KV Z_pu_2 = %i*0.15 ; // p.u impedance V_b1 = 100 ; // base voltage of Tr.1 Z_line = %i*60 ; // Line impedance MVA_M1 = 20 ; // MVA rating of motor load 1 Z_pu_M1 = %i*0.15 ; // p.u impedance of motor load M1 MVA_M2 = 35 ; // MVA rating of motor load 2 Z_pu_M2 = %i*0.25 ; // p.u impedance of motor load M2 MVA_M3 = 25 ; // MVA rating of motor load 3 Z_pu_M3 = %i*0.2 ; // p.u impedance of motor load M3 V_M = 28 ; // voltage across motor loads M1,M2,M3 in kV // Calculations // case a Z_1_pu = Z_pu_1*(MVA_2/MVA_1)*(V_2/V_1)^2 ; // p.u imepedance of T1 // case b Z_2_pu = Z_pu_2*(MVA_2/MVA_1)*(V_2/V_1)^2 ; // p.u imepedance of T2 // case c V_b_line = V_b1*(V_1/V_2) ; // base voltage of the long-transmission line in kV // case d MVA_b = 80 ; // MVA rating V_b = V_b_line ; Z_line_pu = Z_line*(MVA_b/(V_b)^2); // p.u impedance of the transmission line // case e Z_M1_pu = Z_pu_M1 * (MVA_2/MVA_M1)*(V_M/V_1)^2 ; // p.u impedance of motor load M1 Z_M2_pu = Z_pu_M2 * (MVA_2/MVA_M2)*(V_M/V_1)^2 ; // p.u impedance of motor load M2 Z_M3_pu = Z_pu_M3 * (MVA_2/MVA_M3)*(V_M/V_1)^2 ; // p.u impedance of motor load M3 // Display the results disp("Example 14-29 Solution : "); printf(" \n a: p.u imepedance of T1 :\n Z_1(pu) = ");disp(Z_1_pu); printf(" \n b: p.u imepedance of T2 :\n Z_2(pu) = ");disp(Z_2_pu); printf(" \n c: base voltage of the long-transmission line :\n V_b(line) = %.1f kV \n",V_b_line); printf(" \n d: p.u impedance of the transmission line :\n Z(line)_pu = ");disp(Z_line_pu); printf(" \n e: p.u impedance of motor load M1 :\n Z_M1(pu) = ");disp(Z_M1_pu); printf(" \n f: p.u impedance of motor load M1 :\n Z_M2(pu) = ");disp(Z_M2_pu); printf(" \n g: p.u impedance of motor load M1 :\n Z_M3(pu) = ");disp(Z_M3_pu); printf(" \n h: See Fig.14-25b.");