clc;
//Example 25.6
//page no 375
printf("Example 25.6 page no 375\n\n");
//refer to example 25.5
d_p=0.0833//diameter of particles,ft
e=0.4//bed porosity
D_h=2/3*(e/(1-e))*d_p//hydraulic diameter
r_h=D_h/4//hydrulic radius
printf("\n hydraulic diameter D_h=%f ft\n hydrulic radius r_h=%f ft",D_h,r_h);