//Exm[ple 2.2 //Page no. 15 //Given //outer thickness of brickwork (to) & inner thickness (ti) to=0.15 //m ti=0.012 //m //thickness of intermediate layer(til) til=0.07 //m //thermal conductivities of brick and wood kb=0.70 //W/m celcius kw=0.18 //W/m celcius //temp. of outside and inside wall To=-15 //celcius Ti=21 //celcius //area A=1 //m^2 //(a)solution //Thermal resistance of brick , wood and insulating layer TRb=to/(kb*A) //C/W TRw=ti/(kw*A) //C/W TRi=2*TRb //C/W //Total thermal resistance TR=TRb+TRw+TRi //C/W //Temp. driving force T=Ti-To //C //Rate of heat loss Q=T/TR printf("Rate of heat loss is %f W\n",Q) //(b)thermal conductivities of insulating layer k=til/(A*TRi) printf("thermal conductivities of insulating layer is %f W/m C",k)