// Scilab Code Ex10.3.2 Energy released in the fusion of deuterium: Pg:220 (2008) e = 1.6e-019; // Energy equivalent of 1 eV, J/eV Q = 43; // Energy released in fusion of six deuterium atoms, MeV N = 6.023e+026; // Avogadro's number, No. of atoms per kg n = N/2; // Number of atoms contained in 1 kg of deuterium U = Q/6*n*e*1e+06; // Energy released due to fusion of 1 kg of deuterium, J printf("\nThe energy released due to fusion of 1 kg of deuterium = %5.3e J", U); // Result // The energy released due to fusion of 1 kg of deuterium = 3.453e+014 J