From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 944/CH5/EX5.17/example5_17_TACC.sce | 28 ++++++++++++++++++++++++++++
 1 file changed, 28 insertions(+)
 create mode 100755 944/CH5/EX5.17/example5_17_TACC.sce

(limited to '944/CH5/EX5.17')

diff --git a/944/CH5/EX5.17/example5_17_TACC.sce b/944/CH5/EX5.17/example5_17_TACC.sce
new file mode 100755
index 000000000..0944668df
--- /dev/null
+++ b/944/CH5/EX5.17/example5_17_TACC.sce
@@ -0,0 +1,28 @@
+//example 5.17
+
+clear;
+clc;
+
+disp("C3H6(g)+4.5O2(g)-->3CO2(g)+3H2O(l)");
+//Given:
+S=-339.23;//standard change in entropy [J/K]
+T=298;//temperature[K]
+Hf1=20.42;//enthalpy of formation of C3H6(g)[J]
+Hf2=-393.51;//enthalpy of formation of CO2(g)[J]
+Hf3=-285.83;//enthalpy of formation of H2O(l)[J]
+dn=3-4.5-1;//change in no. of moles
+R=8.314;//Universal gas constant[J/K/mol]
+
+//To find the Helmholts free energy and Gibbs free energy
+H=3*Hf2+3*Hf3-Hf1;//Enthalpy of the reaction[J]
+U=H-dn*R*0.001*T;//Change in internal energy of the reaction[J]
+A=U-T*S*0.001;//Helmholts free energy change[J]
+G=A+dn*R*0.001*T;//Gibbs free energy change[J]
+printf("The change in Helmholts free energy is %f J",A);
+printf("\nThe change in Gibbs free energy is %f J ",G);
+
+
+
+
+
+
-- 
cgit