From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 926/CH3/EX3.5/Chapter3_Example5.sce | 29 +++++++++++++++++++++++++++++ 1 file changed, 29 insertions(+) create mode 100644 926/CH3/EX3.5/Chapter3_Example5.sce (limited to '926/CH3/EX3.5/Chapter3_Example5.sce') diff --git a/926/CH3/EX3.5/Chapter3_Example5.sce b/926/CH3/EX3.5/Chapter3_Example5.sce new file mode 100644 index 000000000..cda2af729 --- /dev/null +++ b/926/CH3/EX3.5/Chapter3_Example5.sce @@ -0,0 +1,29 @@ +//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504 + +//Chapter-3, Illustration 5, Page 55 +//Title: Calculation of percentage dissociation of gas +//============================================================================= +clear +clc + +//INPUT +W = 17.2; //Weight of N2O4 in grams +V1 = 11450; //Volume occupied by N2O4 in cc +P1 = 720; //Given pressure in mm hg +T = 100; //Given temperature in degree C +MW = 92; //Molecular weight of N2O4 in g/g mole +V2 = 22400; //Volume at standard conditions in cc +P2 = 760; //Pressure at standard conditions in mm Hg +T2 = 273; //Temperature at standard conditions in K + +//CALCULATIONS +T1 = T+273; //Given temperature in K +n1 = W/MW; //No of moles of N2O4 initially present in g mole +n2 = (V1/V2)*(T2/T1)*(P1/P2); //Total g moles present after dissociation +x = n2-n1; //g moles of N2O4 dissociated +X = x*100/n1; //Percentage dissociation + +//OUTPUT +mprintf('\n Percentage dissociation of N2O4 to NO2 is %2.0f percent',X); + +//=========================END OF PROGRAM====================================== \ No newline at end of file -- cgit