From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 659/CH7/EX7.2/exm7_2.sce        |  42 ++++++++++++++++++++++++++++++++++++++++
 659/CH7/EX7.2/exm7_2_output.PNG | Bin 0 -> 18313 bytes
 2 files changed, 42 insertions(+)
 create mode 100755 659/CH7/EX7.2/exm7_2.sce
 create mode 100755 659/CH7/EX7.2/exm7_2_output.PNG

(limited to '659/CH7/EX7.2')

diff --git a/659/CH7/EX7.2/exm7_2.sce b/659/CH7/EX7.2/exm7_2.sce
new file mode 100755
index 000000000..bb64796ac
--- /dev/null
+++ b/659/CH7/EX7.2/exm7_2.sce
@@ -0,0 +1,42 @@
+//                    Example:7.2
+//Given below is the list of marks obtained by a class of 50 students in an 
+//annual examination. 43 65 51 27 79 11 56 61 82 09 25 36 07 49 55 63 74 81 49 
+//37 40 49 16 75 87 91 33 24 58 78 65 56 76 67 45 54 36 63 12 21 73 49 51 19 39 
+//49 68 93 85 59
+//Write a program to count the number of students belonging to each of
+// following groups of marks:0-9,10-19,20-29,.......100.
+
+//This program computes for 10 students. We could compute for 50 students by
+//changing MAXVAL=50.
+
+MAXVAL=10;COUNTER=11;
+disp("Input Data[Marks of 10 students]");
+group1=zeros(1,11);
+//Reading and counting
+for i=1:MAXVAL
+    //Reading of values
+    value(i)=input(" ");
+    //Counting frequency of groups
+    a=int16((value(i)/10));
+    if(a==0) then
+      group1(a+1)=group1(a+1)+1;
+     else
+      group1(a+1)=group1(a+1)+1;
+    end
+  
+end
+//Printing of frequency table
+printf("Group       Range     Frequency\n");
+for i=0:COUNTER-1
+    if(i==0) ,
+        low=0;
+    else
+        low=i*10;
+    end
+    if(i==10),
+        high=100;
+     else
+          high=low+9;
+    end
+    printf("%2d %8d to %3d %5d\n",i+1,low,high,group1(i+1));
+end
diff --git a/659/CH7/EX7.2/exm7_2_output.PNG b/659/CH7/EX7.2/exm7_2_output.PNG
new file mode 100755
index 000000000..4b12a2e5f
Binary files /dev/null and b/659/CH7/EX7.2/exm7_2_output.PNG differ
-- 
cgit