From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

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+// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India.
+
+//Chapter-12,Example 9,Page 464
+//Title: Temperature-composition diagram
+//================================================================================================================
+clear 
+clc
+
+//INPUT
+//For convenience benzene is taken as 1 and water is taken as 2. They form a completely immiscible system
+P=760;//pressure of the system in Torr
+antoine_const_benzene=[6.87987;1196.760;219.161];//Antoine's constants for Benzene from Table A.7
+t=60:5:100;//temperature range in degree celsius
+//saturation pressure of water(in torr)in the temperature range given by t (from steam tables)
+P2_s=[149.40;187.58;233.71;289.13;355.21;433.51;525.84;634.00;760.00];
+x1=0:0.2:1;//mole fraction of benzene in the liquid phase (no unit) (taken in an arbitrary manner)
+
+//CALCULATION
+//The form of the Antoine's equation used is logP=A-(B/(t+C)), where P is in Torr and t is in degree celsius
+//The three phase equilibrium temperature is estimated using the saturation pressure values,such that at the three phase equilibrium temperature,P=P1_s+P2_s=P as given by Eq.(12.57) Torr
+l=length(t);//iteration parameter
+i=1;//iteration parameter
+while i<l|i==l
+//calculation of saturation pressure of benzene at T in Torr
+P1_s(i)=10^(antoine_const_benzene(1,:)-(antoine_const_benzene(2,:)/(t(:,i)+antoine_const_benzene(3,:))));
+//calculating the total pressure in Torr so as to narrow down the temperature range for estimating the three phase equilibrium temperature
+P_tot(i)=P1_s(i)+P2_s(i,:);
+i=i+1;
+end
+//From the P_tot values calculated above, it is observed that the temperature range in which the three phase equilibrium temperature lies,is in between 65 and 70   degree celsius. Using linear interpolation , the three phase equilibrium temperature is determined in degree celsius
+T=(((t(:,3)-t(:,2))*(760-P_tot(2,:)))/(P_tot(3,:)-P_tot(2,:)))+t(:,2);//linear interpolation to determine the three phase equilibrium temperature in degree celsius
+//calculation of saturation pressure of benzene at the three phase temperature in Torr
+P1_s_three_phase=10^(antoine_const_benzene(1,:)-(antoine_const_benzene(2,:)/(T+antoine_const_benzene(3,:))));
+P2_s_three_phase=760-P1_s_three_phase;//calculation of the saturation pressure of water at the three phase temperature in Torr
+y1_three_phase=P1_s_three_phase/760;//calculation of the mole fraction of benzene in the vapour phase at the three phase equilibrium point (no unit)
+//redefining the temeprature range in degree celsius for computing the vapour compositions in the two phase regions. (As the three phase equilibrium temperature  lies between 65 and 70 degree celsius)
+//The normal boiling point of benzene is given as 80.1 degree celsius (at a pressure of 760 Torr)
+trange1=T:1:T+11;//temperature range for calculating vapour phase composition of benzene in the two phase region given by (L1+V)
+n=length(trange1);//iteration parameter
+i=1;//iteration parameter
+while i<n|i==n
+    if i==1 then
+        y1(i)=y1_three_phase;//calculation of the vapour composition of benzene in the two phase region (L1+V) using Eq.(12.59) (no unit)
+    else
+         P1_s_calc(i)=10^(antoine_const_benzene(1,:)-(antoine_const_benzene(2,:)/(trange1(:,i)+antoine_const_benzene(3,:))));
+    y1(i)=(P1_s_calc(i))/P;//calculation of the vapour composition of benzene in the two phase region (L1+V) using Eq.(12.59) (no unit)
+    end
+    i=i+1;
+end
+trange2=[70;75;80;85;90;95;100];//temperature range for calculating vapour phase composition of benzene in the two phase region given by (L2+V)
+P2_s_range=[233.71;289.13;355.21;433.51;525.84;634.00;760.00];//saturation pressure of water(in torr)in the temperature range given by trange2 (from steam tables)
+p=length(trange2);//iteration parameter
+i=1;//iteration parameter
+//calculation of the vapour composition of benzene in the two phase region (L2+V) using Eq.(12.61) (no unit)
+y_one(i)=y1_three_phase;
+trange2(i)=T;
+i=i+1;
+while i<p|i==p
+        y_one(i)=(P-P2_s_range(i,:))/P;
+    i=i+1;
+end
+i=1;//iteration parameter
+k=length(x1);//iteration parameter
+while i<k|i==k
+    t_3phase(i)=T;//creating a vector for generating the plot at the three phase temperature
+    i=i+1;
+end
+
+//OUTPUT
+//Generating the T-x-y plot for the benzene-water system 
+plot(y1,trange1);
+plot(y_one,trange2);
+plot(x1,t_3phase);
+ xtitle('t-x-y diagram for benzene-water sytem at 760 Torr','x1,y1','t (degree celsius)');
+q=length(t);//iteration parameter
+i=1;//iteration parameter
+mprintf('Calculations performed for determining the three phase equilibrium temperature\n');
+mprintf('t(degree celsius) \t P1_s (Torr) \t P2_s (Torr) \t P1_s+P2_s (Torr) \n');
+for i=1:q
+    mprintf('%d \t \t \t %f \t %0.2f \t %f \n',t(i),P1_s(i),P2_s(i),P_tot(i));
+end
+mprintf('The three phase equilibrium temperature=%0.2f degree celsius \n',T);
+mprintf('The vapour phase composition of benzene at the three phase equilibrium point=%0.4f \n',y1_three_phase);
+//===============================================END OF PROGRAM===================================================
+
+
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