From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 608/CH7/EX7.14/7_14.sce | 27 +++++++++++++++++++++++++++ 1 file changed, 27 insertions(+) create mode 100755 608/CH7/EX7.14/7_14.sce (limited to '608/CH7/EX7.14/7_14.sce') diff --git a/608/CH7/EX7.14/7_14.sce b/608/CH7/EX7.14/7_14.sce new file mode 100755 index 000000000..b3953c0ce --- /dev/null +++ b/608/CH7/EX7.14/7_14.sce @@ -0,0 +1,27 @@ +//Problem 7.14: A section through a magnetic circuit of uniform cross-sectional area 2 cm2 is shown in Figure 7.5. The cast steel core has a mean length of 25 cm. The air gap is 1 mm wide and the coil has 5000 turns. The B–H curve for cast steel is shown on page 78. Determine the current in the coil to produce a flux density of 0.80 T in the air gap, assuming that all the flux passes through both parts of the magnetic circuit. + +//initializing the variables: +A = 2E-4; // in m2 +l1 = 0.25; // in m +l2 = 0.001; // in m +u0 = 4*%pi*1E-7; +N = 5000; // no. of turns +B = 0.8; // in tesla +ua = 1; // for air + +//calculation: +//for the core +//From the B–H curve for Mild steel, corresponding to value of B = 0.8 +H = 750 +ur = B/(u0*H) +S1 = l1/(u0*ur*A) +//For the air gap: +S2 = l2/(u0*ua*A) +St = S1 + S2 +//flux +Phi = B*A +//current +I = St*Phi/N + +printf("\n\nResult\n\n") +printf("\n current = %.3f A",I) \ No newline at end of file -- cgit