From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 608/CH39/EX39.02/39_02.sce | 17 +++++++++++++++++
 1 file changed, 17 insertions(+)
 create mode 100755 608/CH39/EX39.02/39_02.sce

(limited to '608/CH39/EX39.02/39_02.sce')

diff --git a/608/CH39/EX39.02/39_02.sce b/608/CH39/EX39.02/39_02.sce
new file mode 100755
index 000000000..8f7e1d88b
--- /dev/null
+++ b/608/CH39/EX39.02/39_02.sce
@@ -0,0 +1,17 @@
+//Problem 39.02: A capacitor has a loss angle of 0.025 rad, and when it is connected across a 5 kV, 50 Hz supply, the power loss is 20 .W Determine the component values of the equivalent parallel circuit.
+
+//initializing the variables:
+del = 0.025; // in rad.
+V = 5000; // in Volts
+PL = 20; // power loss
+f = 50; // in Hz
+
+//calculation: 
+//power loss = w*C*V^2*tan(del)
+Cp = PL/(2*%pi*f*V*V*tan(del))
+//for a parallel equivalent circuit,
+//tan(del) = 1/(Rp*w*Cp)
+Rp = 1/(2*%pi*f*Cp*tan(del))
+
+printf("\n\n Result \n\n")
+printf("\n capacitance C %.2E F and parallel resistance %.2E ohm.",Cp, Rp)
\ No newline at end of file
-- 
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