From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 608/CH28/EX28.04/28_04.sce | 34 ++++++++++++++++++++++++++++++++++
 1 file changed, 34 insertions(+)
 create mode 100755 608/CH28/EX28.04/28_04.sce

(limited to '608/CH28/EX28.04')

diff --git a/608/CH28/EX28.04/28_04.sce b/608/CH28/EX28.04/28_04.sce
new file mode 100755
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+//Problem 28.04: A series circuit comprises a 10 ohm resistance, a 5 μF capacitor and a variable inductance L. The supply voltage is 20/_0° volts at a frequency of 318.3 Hz. The inductance is adjusted until the p.d. across the 10 ohm resistance is a maximum. Determine for this condition (a) the value of inductance L, (b) the p.d. across each component and (c) the Q-factor.
+
+//initializing the variables:
+R = 10; // in ohms
+C = 5e-6; // IN fARADS
+rv = 20; //in volts
+thetav = 0; // in degrees
+f = 318.3; // in Hz
+
+//calculation:
+wr = 2*%pi*f
+//The maximum voltage across the resistance occurs at resonance when the current is a maximum. At resonance,L = 1/c*wr^2
+L = 1/(C*wr^2)
+//voltage
+V = rv*cos(thetav*%pi/180) + %i*rv*sin(thetav*%pi/180)
+//Current at resonance Ir
+Ir = V/R
+//p.d. across resistance, VR
+VR = Ir*R
+//inductive reactance, XL
+XL = wr*L
+//p.d. across inductance, VL
+VL = Ir*(%i*XL)
+//capacitive reactance, Xc
+Xc = 1/(wr*C)
+//p.d. across capacitor, Vc
+Vc = Ir*(-1*%i*Xc)
+//Q-factor at resonance, Qr
+Qr = imag(VL)/V
+
+printf("\n\n Result \n\n")
+printf("\n (a)inductance, L is %.2E H ",L)
+printf("\n (b)p.d. across resistance, VR is %.2f V, p.d. across inductance, VL %.0fi V and p.d. across capacitor, VC %.0fi V ",VR, imag(VL), imag(Vc))
+printf("\n (c)Q-factor at resonance, Qr is %.0f  ",Qr)
\ No newline at end of file
-- 
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