From f35ea80659b6a49d1bb2ce1d7d002583f3f40947 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:38:01 +0530
Subject: updated the code

---
 608/CH21/EX21.21/21_21.sce | 38 +++++++++++++++++++-------------------
 1 file changed, 19 insertions(+), 19 deletions(-)

(limited to '608/CH21/EX21.21/21_21.sce')

diff --git a/608/CH21/EX21.21/21_21.sce b/608/CH21/EX21.21/21_21.sce
index 2cc2c0368..2311a2062 100755
--- a/608/CH21/EX21.21/21_21.sce
+++ b/608/CH21/EX21.21/21_21.sce
@@ -1,20 +1,20 @@
-//Problem 21.21: A 200 V, d.c. shunt-wound motor has an armature resistance of 0.4 ohm and at a certain load has an armature current of 30 A and runs at 1350 rev/min. If the load on the shaft of the motor is increased so that the armature current increases to 45 A, determine the speed of the motor, assuming the flux remains constant.
-
-//initializing the variables:
-Ia1 = 30; // in Amperes
-Ia2 = 45; // in Amperes
-Ra = 0.4; // in ohm
-n1 = 1350/60; // in Rev/sec
-V = 200; // in Volts
-
-//calculation:
-//The relationship E proportional to (Phi*n) applies to both generators and motors. For a motor,
-//E = V - (Ia*Ra)
-E1 =  V - (Ia1*Ra)
-E2 =  V - (Ia2*Ra)
-//The relationship, E1/E2 = Phi1*n1/Phi2*n2,  applies to both generators and motors. Since the flux is constant, Phi1 = Phi2
-Phi2 = Phi1
-n2 = E2*Phi1*n1/(Phi2*E1)
-
-printf("\n\n Result \n\n")
+//Problem 21.21: A 200 V, d.c. shunt-wound motor has an armature resistance of 0.4 ohm and at a certain load has an armature current of 30 A and runs at 1350 rev/min. If the load on the shaft of the motor is increased so that the armature current increases to 45 A, determine the speed of the motor, assuming the flux remains constant.
+
+//initializing the variables:
+Ia1 = 30; // in Amperes
+Ia2 = 45; // in Amperes
+Ra = 0.4; // in ohm
+n1 = 1350/60; // in Rev/sec
+V = 200; // in Volts
+
+//calculation:
+//The relationship E proportional to (Phi*n) applies to both generators and motors. For a motor,
+//E = V - (Ia*Ra)
+E1 =  V - (Ia1*Ra)
+E2 =  V - (Ia2*Ra)
+//The relationship, E1/E2 = Phi1*n1/Phi2*n2,  applies to both generators and motors. Since the flux is constant, Phi1 = Phi2
+//Phi2 = Phi1
+n2 = E2*n1/(E1)
+
+printf("\n\n Result \n\n")
 printf("\n the speed of the motor is %.2f rev/sec ",n2)
\ No newline at end of file
-- 
cgit