From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 608/CH21/EX21.09/21_09.sce | 25 +++++++++++++++++++++++++
 1 file changed, 25 insertions(+)
 create mode 100755 608/CH21/EX21.09/21_09.sce

(limited to '608/CH21/EX21.09')

diff --git a/608/CH21/EX21.09/21_09.sce b/608/CH21/EX21.09/21_09.sce
new file mode 100755
index 000000000..440c1f519
--- /dev/null
+++ b/608/CH21/EX21.09/21_09.sce
@@ -0,0 +1,25 @@
+//Problem 21.09: A separately-excited generator develops a no-load e.m.f. of 150 V at an armature speed of 20 rev/s and a flux per pole of 0.10 Wb. Determine the generated e.m.f. when (a) the speed increases to 25 rev/s and the pole flux remains unchanged, (b) the speed remains at 20 rev/s and the pole flux is decreased to 0.08 Wb, and (c) the speed increases to 24 rev/s and the pole flux is decreased to 0.07 Wb.
+
+//initializing the variables:
+E1 = 150; // in Volts
+n1 = 20; // in rev/sec
+Phi1 = 0.10; // in Wb
+n2 = 25; // in rev/sec
+Phi2 = 0.10; // in Wb
+n3 = 20; // in rev/sec
+Phi3 = 0.08; // in Wb
+n4 = 24; // in rev/sec
+Phi4 = 0.07; // in Wb
+
+//calculation:
+//generated e.m.f., E proportional to phi*w and since w = 2*pi*n, then
+// E proportional to phi*n
+// E1/E2 = Phi1*n1/(Phi2*n2)
+E2 = E1*Phi2*n2/(Phi1*n1)
+E3 = E1*Phi3*n3/(Phi1*n1)
+E4 = E1*Phi4*n4/(Phi1*n1)
+
+printf("\n\n Result \n\n")
+printf("\n (a)the generated e.m.f is %.1f V ",E2)
+printf("\n (b)generated e.m.f. is %.0f V ",E3)
+printf("\n (c)generated e.m.f. is %.0f V ",E4)
\ No newline at end of file
-- 
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