From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 608/CH13/EX13.20/13_20.jpg | Bin 0 -> 21012 bytes
 608/CH13/EX13.20/13_20.sce |  13 +++++++++++++
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 create mode 100755 608/CH13/EX13.20/13_20.sce

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diff --git a/608/CH13/EX13.20/13_20.jpg b/608/CH13/EX13.20/13_20.jpg
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diff --git a/608/CH13/EX13.20/13_20.sce b/608/CH13/EX13.20/13_20.sce
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+//Problem 13.20: The circuit diagram of Figure 13.48 shows dry cells of source e.m.f. 6 V, and internal resistance 2.5 ohm. If the load resistance RL is varied from 0 to 5 ohm in 0.5 ohm  steps, calculate the power dissipated by the load in each case. Plot a graph of RL (horizontally) against power (vertically) and determine the maximum power dissipated.
+
+//initializing the variables:
+V = 6; // in volts
+r = 2.5; // in ohms
+
+//calculation:
+RL=(0:0.5:5)';
+function [y]=f(RL)
+    y = RL*(V/(r + RL))^2;
+endfunction
+fplot2d(RL, f)
+xtitle("graph of (RL) against power(P)", "RL(ohm)", "P(W)")
\ No newline at end of file
-- 
cgit