From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 608/CH13/EX13.19/13_19.sce | 37 +++++++++++++++++++++++++++++++++++++
 1 file changed, 37 insertions(+)
 create mode 100755 608/CH13/EX13.19/13_19.sce

(limited to '608/CH13/EX13.19')

diff --git a/608/CH13/EX13.19/13_19.sce b/608/CH13/EX13.19/13_19.sce
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+//Problem 13.19: Determine by successive conversions between Th´evenin and Norton equivalent networks a Th´evenin equivalent circuit for terminals AB of Figure 13.46(a). Hence determine the current flowing in the 200 ohm resistance.
+
+//initializing the variables:
+V1 = 10; // in volts
+V2 = 6; // in volts
+R1 = 2000; // in ohms
+R2 = 3000; // in ohms
+R3 = 600; // in ohms
+R4 = 200; // in ohms
+i = 0.001; // in amperes
+
+//calculation:
+//For the branch containing the V1 source, converting to a Norton equivalent network gives
+Isc1 = V1/R1
+r1 = R1
+//For the branch containing the V2 source, converting to a Norton equivalent network gives
+Isc2 = V2/R2
+r2 = R2
+//Thus the network of Figure 13.46(a) converts to Figure 13.46(b).
+//total short-circuit current
+Isct = Isc1 + Isc2
+//the resistance is
+z = r1*r2/(r1 + r2)
+//Both of the Norton equivalent networks shown in Figure 13.46(c) may be converted to Th´evenin equivalent circuits. The open-circuit voltage across CD is
+Vcd = Isct*z
+//The open-circuit voltage across EF is
+Vef = i*R3
+//the resistance ‘looking-in’ at EF is
+r3 = R3
+//Thus Figure 13.46(c) converts to Figure 13.46(d). Combining the two Th´evenin circuits gives
+E = Vcd - Vef
+r = z + r3
+//the current I flowing in a 200 ohm resistance connected between A and B is given by:
+I = E/(r + R4)
+
+printf("\n\n Result \n\n") 
+printf("\n the current I flowing in a 200ohm resistance connected between A and B is given by:is %.2E A",I)
\ No newline at end of file
-- 
cgit