From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 599/CH6/EX6.1/example6_1.sce | 33 +++++++++++++++++++++++++++++++++
 1 file changed, 33 insertions(+)
 create mode 100755 599/CH6/EX6.1/example6_1.sce

(limited to '599/CH6/EX6.1/example6_1.sce')

diff --git a/599/CH6/EX6.1/example6_1.sce b/599/CH6/EX6.1/example6_1.sce
new file mode 100755
index 000000000..422ea7a86
--- /dev/null
+++ b/599/CH6/EX6.1/example6_1.sce
@@ -0,0 +1,33 @@
+
+clear;
+clc;
+printf("\t Example 6.1\n");
+
+    //air leaves the pre-heater of the dryer at 325K
+
+H1=.005;                        //humidity of incoming air per kg of dry air
+T1=25;                          //wet bulb temperature
+    //moisture is removed along constant wet bulb temp. till 60per R.H is reached
+// from the chart ,humidity of ai rleaving first shelf =.016 kg water /kg dry air.
+
+//dry bulb temp. of exit air is at 27 degree aand is at humidity of .016 kg water/kg dry air.the air is again heated to 52 degree dry bulb temp. in 2nd heater .
+
+    //so air leaves heater at 52 degree and humidity of .016 kg water/kg dry air. when it leaves the 2nd shelf the correspondin dry bulb temp. is 34 degree and humidity is .023 kg water/kg dry air. the air enters the 3rd shelf after preheating to 52 degree . 
+    
+//similarly fro 3rd shelf , exit air has a humidity of .028 kg water/kg dry air and adry bulb temp. is 39 degree. the air is leaving the 4rth shelf has a humidity of .016 kg water/kg dry air and adry bulb temp. of 42 degree(the figure is only indicative and doed not correspond toactual one)
+
+printf("\n  the solid temp. correspond to wbt and they are 23, 27,32 and 34  degree respectively");
+
+        //part(ii)
+Ybar=.032;                 //kg water/kg dry air//final moist air condotions 
+T2=42;                    //dry bulb temperature
+Mair=28.84;               //molecular weight of air 
+Mwater=18;                  //molecular weight of water
+pt=1.013*10^5;            //total pressure in pascal
+Vh=8315*((1/Mair)+(Ybar/Mwater))*((T2+273)/pt);
+r=300;                    //flow rate of moist air leaving the dryer
+a=r*60/Vh;               //amount of dry air leaving /hr
+w=a*(Ybar-0.005);         // water removed /hr
+printf("\n the water removed /hr is :%fkg /hr",w);
+
+//end
\ No newline at end of file
-- 
cgit