From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 593/CH4/EX4.3/ex4_3.sce | 25 +++++++++++++++++++++++++
 1 file changed, 25 insertions(+)
 create mode 100755 593/CH4/EX4.3/ex4_3.sce

(limited to '593/CH4/EX4.3')

diff --git a/593/CH4/EX4.3/ex4_3.sce b/593/CH4/EX4.3/ex4_3.sce
new file mode 100755
index 000000000..da95ca411
--- /dev/null
+++ b/593/CH4/EX4.3/ex4_3.sce
@@ -0,0 +1,25 @@
+clear;
+//clc();
+
+// Example 4.3
+// Page: 80
+printf("Example-4.3  Page no.-80\n\n");
+
+//***Data***//
+// We have the system which consists of isobutane and normal butane and isomerisaation is taking place between them 
+// The equilibrium constant for this reaction is given by
+// K = (mole fraction of isobutane)/(mole fraction of n-butane) = x_iso/x_normal
+
+// For this reaction, at 25C, 
+K = 4.52;
+
+// and
+// x_iso + x_normal = 1
+// so
+// K = x_iso/(1-x_iso)
+
+// solving for x_iso
+deff('[y]=f(x_iso)','y = x_iso/(1-x_iso)-K');
+x_iso = fsolve(0,f);
+
+printf(" Mole fraction of isobutane isomer in equilibrium is %0.2f",x_iso);
-- 
cgit