From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001 From: priyanka Date: Wed, 24 Jun 2015 15:03:17 +0530 Subject: initial commit / add all books --- 527/CH2/EX2.20/2_20exam.sce | 79 +++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 79 insertions(+) create mode 100755 527/CH2/EX2.20/2_20exam.sce (limited to '527/CH2/EX2.20/2_20exam.sce') diff --git a/527/CH2/EX2.20/2_20exam.sce b/527/CH2/EX2.20/2_20exam.sce new file mode 100755 index 000000000..78508cc93 --- /dev/null +++ b/527/CH2/EX2.20/2_20exam.sce @@ -0,0 +1,79 @@ +//Engineering and Chemical Thermodynamics +//Example 2.20 +//Page no :89 + +clear ; clc ; +//solution (a) +//Given data +Cv = 3/2 * 8.314 ; +Cp = 5/2 * 8.314 ; +n = 1; +R = 8.314 ; +T1 = 1000 ; //[K] +P1 = 10 ; //[bar] +T2 = 1000 ; //[K] +P2 = 0.1 ; //[bar] +T3 = 300 ; //[K] +T4 = 300 ; //[K] + +k = Cp / Cv ; +P3 = P2 * (T3 / T2)^(k/(k-1)); //[bar] +P4 = P1 * (T4 / T1)^(k/(k-1)) ; //[bar] + +// (1) + del_U_12 = 0 ; // As process 1-2 is isothermal + W_12 = n * R * T1 * log(P2 / P1); + Q_h_12 = W_12 ; + disp(" Example: 2.20 Page no : 89") ; +printf('(a)\n (1)\n del_U = %d J',del_U_12) ; +printf('\n Work = %d J',W_12) ; +printf('\n Heat = %d J',Q_h_12) ; + +//(2) + Q_23 = 0 ; // As adiabatic process + del_U_23 = n * Cv *(T3 - T2) ; + W_23 = del_U_23 ; +printf('\n (2)\n del_U = %g J',del_U_23) ; +printf('\n Work (J) = %d J',W_23) ; +printf('\n Heat (J) = %d J',Q_23) ; + +//(3) + del_U_34 = 0 ; // As isothermal process + W_34 = n * R * T3 * log(P4 / P3) ; // Eqn E2.20.A + Q_c_34 = del_U_34 - W_34 ; +printf('\n (3)\n del_U = %g J',del_U_34) ; +printf('\n Work = %d J',W_34) ; +printf('\n Heat = %d J',Q_c_34) ; + +//(4) + Q_41 = 0 ; // As adiabatic process + del_U_41 = n * Cv * (T1 - T4) ; + W_41 = del_U_41 ; +printf('\n (4)\n del_U = %g J',del_U_41) ; +printf('\n Work = %d J',W_41) ; +printf('\n Heat = %d J',Q_41) ; + +//Solution (b) +//Users can refer figure E2.20 + +//Solution (c) + W_total = W_12 + W_23 + W_34 + W_41 ; + Q_absor = Q_h_12 ; + effi = W_total / Q_absor ; +printf('\n\n(c) efficiency = %g',effi) + +//Solution (d) +x = 1 - T3 / T1 ; +printf('\n\n(d) 1 - Tc/Th = %g',x); +disp(" i.e Efficiency = 1 - Tc/Th"); + +//Solution (e) +disp("(e) The process can be made more efficient by raising Th or by lowering Tc ."); +disp("Table E2.20B") ; +disp(" T(K) P(bar) v(m^3/mol)") ; +P = [P1 , P2 , P3 , P4 ] ; +T = [T1 , T2 , T3 , T4 ] ; +for i = 1:4 + v(i) = R * T(i) * 10^-5/ P(i) ; + printf("\n %d %.4f %f \n",T(i) ,P(i) ,v(i)) ; +end -- cgit