From b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b Mon Sep 17 00:00:00 2001
From: priyanka
Date: Wed, 24 Jun 2015 15:03:17 +0530
Subject: initial commit / add all books

---
 405/CH7/EX7.6/7_6.sce | 30 ++++++++++++++++++++++++++++++
 1 file changed, 30 insertions(+)
 create mode 100755 405/CH7/EX7.6/7_6.sce

(limited to '405/CH7/EX7.6/7_6.sce')

diff --git a/405/CH7/EX7.6/7_6.sce b/405/CH7/EX7.6/7_6.sce
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+clear;
+clc;
+printf("\t\t\tExample Number 7.6\n\n\n");
+// cube cooling in air
+// Example 7.6 (page no.-336) 
+// solution
+
+L = 0.2;// [m] side length of cube
+Ts = 60;// [degree celsius] surface temperature of cube
+Ta = 10;// [degree celsius] air temperature
+// this is an irregular solid so we use the information in the last entry of table 7-1(page no.-328) in the absence of a specific correlation for this    geometry. 
+// the properties were evaluated as
+v = 17.47*10^(-6);// [square meter/s]
+k = 0.02685;// [W/m degree celsius]
+Pr = 0.70;// prandtl number
+Beta = 3.25*10^(-3);// [K^(-1)]
+g = 9.8;// [square meter/s] acceleration due to gravity 
+// the characteristic length is the distance a particle travels in the boundary layer, which is L/2 along the bottom plus L along the side plus L/2 on  the top or
+Gr_into_Pr = (g*Beta*(Ts-Ta)*(2*L)^(3)*Pr)/(v^(2));
+// from the last entry in table 7-1 we find
+C = 0.52;
+n = 1/4;
+// so that
+Nu = C*(Gr_into_Pr)^(n);
+h_bar = Nu*k/(2*L);// [W/square meter degree celsius]
+// the cube has six sides so the area is 
+A = 6*L^(2);// [square meter]
+// the heat required is 
+q = h_bar*A*(Ts-Ta);// [W]
+printf("heat transfer is %f W",q);
-- 
cgit