From 7bc77cb1ed33745c720952c92b3b2747c5cbf2df Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Sat, 3 Feb 2018 11:01:52 +0530 Subject: Added new code --- 3888/CH4/EX4.6/Ex4_6.sce | 41 +++++++++++++++++++++++++++++++++++++++++ 1 file changed, 41 insertions(+) create mode 100644 3888/CH4/EX4.6/Ex4_6.sce (limited to '3888/CH4/EX4.6/Ex4_6.sce') diff --git a/3888/CH4/EX4.6/Ex4_6.sce b/3888/CH4/EX4.6/Ex4_6.sce new file mode 100644 index 000000000..ec1812424 --- /dev/null +++ b/3888/CH4/EX4.6/Ex4_6.sce @@ -0,0 +1,41 @@ +//Electric Power Generation, Transmission and Distribution by S.N.Singh +//Publisher:PHI Learning Private Limited +//Year: 2012 ; Edition - 2 +//Example 4.6 +//Scilab Version : 6.0.0 ; OS : Windows + + +clc; +clear; + + +k=0.6; +t=1.503032/0.6; //Time in hours +Df=3; //Density factor +P=30- 8*sin(k*t)+0.325*t; //Load variation at a power supply station in MW +i=1; +n=1; +while (t(i)<24) +t(i+1)=(2*n*%pi-1.503032)/0.6; +t(i+2)=(2*n*%pi+1.503032)/0.6; +if (t(i+1)<24)&(t(i+2)<24) then + i=i+2; +else + t(i+1)=25; + i=i+1; +end +n=n+1; +end +P=30- 8*sin(k*t)+0.325*t; +Max_demand=max(P); //Maximum demand on the system in MW +Avg_load=(1/24)*(30*24+(8/0.6)*(cosd(0.6*24)-cosd(0.6*0))+0.325*24^(2)/2); //Applying integration for power equation +Lf=Avg_load/Max_demand; //Load factor of the system +Total_load=Max_demand*Df; //Total installed load of the system in MW + + +printf("\nMaximum demand on the system is %.3f MW",Max_demand); +printf("\nLoad factor of the system %.3f",Lf); +printf("\nTotal installed load is %.3f MW",Total_load); + //different t values cannot be obtained for section d so cannot be solved in scilab + //Variation present in result due to wrong calculation of Avg load value in the book + -- cgit