From 7bc77cb1ed33745c720952c92b3b2747c5cbf2df Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Sat, 3 Feb 2018 11:01:52 +0530
Subject: Added new code

---
 3886/CH4/EX4.12/Ex4_12.sce | 38 ++++++++++++++++++++++++++++++++++++++
 1 file changed, 38 insertions(+)
 create mode 100644 3886/CH4/EX4.12/Ex4_12.sce

(limited to '3886/CH4/EX4.12/Ex4_12.sce')

diff --git a/3886/CH4/EX4.12/Ex4_12.sce b/3886/CH4/EX4.12/Ex4_12.sce
new file mode 100644
index 000000000..ab6e62458
--- /dev/null
+++ b/3886/CH4/EX4.12/Ex4_12.sce
@@ -0,0 +1,38 @@
+//Analyse the truss
+//Refer fig. 4.20
+//Consider equilibrium of entire truss
+//taking moment about A
+YE=(60*8-40*4)/4   //kN
+XA=40  //kN
+YA=60-80  //kN
+//Take A as origin and determine co-ordinates of various point
+//Lengths in m are
+AB=4
+CE=4
+AE=4
+ED=4
+BE=4*sqrt(2)
+CD=4*sqrt(2)
+//Consider equilibrium of joints individually
+//Joint A
+tAB=5
+FAB=tAB*AB  //kN
+tAE=-10
+FAE=tAE*AE  //kN
+//Joint B
+tBE=-5
+FBE=tBE*BE  //kN
+tBC=10-tBE
+BC=4
+FBC=tBC*BC  //kN
+//Joint C
+tCD=15
+CD=4*sqrt(2)  
+FCD=15*4*sqrt(2)  //kN  The answer provided in the textbook is wrong
+tCE=-15
+FCE=tCE*CE  //kN
+//Joint D
+tDE=-15
+DE=4
+FDE=tDE*DE  //kN
+printf("The forces in different members are:-\nAB=%.2d kN\nBC=%.2d kN\nCD=%.2d kN\nDE=%.2d kN\nEA=%.2d kN\nEC=%.2d kN\nEB=%.2d kN",FAB,FBC,FCD,FDE,FAE,FCE,FBE)
-- 
cgit