From 7bc77cb1ed33745c720952c92b3b2747c5cbf2df Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Sat, 3 Feb 2018 11:01:52 +0530
Subject: Added new code

---
 3886/CH4/EX4.11/Ex4_11.sce | 30 ++++++++++++++++++++++++++++++
 1 file changed, 30 insertions(+)
 create mode 100644 3886/CH4/EX4.11/Ex4_11.sce

(limited to '3886/CH4/EX4.11/Ex4_11.sce')

diff --git a/3886/CH4/EX4.11/Ex4_11.sce b/3886/CH4/EX4.11/Ex4_11.sce
new file mode 100644
index 000000000..0f916a380
--- /dev/null
+++ b/3886/CH4/EX4.11/Ex4_11.sce
@@ -0,0 +1,30 @@
+//Analyse the truss by method of tension coefficient to determine the forces 
+//Refer fig.4.19
+//Consider entire structure
+//Taking moment about A
+YD=(40*2+50*6+30*4*sind(60)+60*4)/8
+XA=-30  //kN
+YA=40+50+60-90.49  //kN
+//Take A as origin and determine co-ordinates of all other point
+//Consider equilibrium of individual joints
+//Joint A
+tAB=-(59.51/3.464)
+FAB=tAB*4  //kN
+tAE=64.36/4
+FAE=tAE*4  //kN
+//Joint B
+tBE=-11.547+17.18
+FBE=tBE*4  //kN
+tBC=0.5*(-17.18-5.637)
+FBC=tBC*4  //kN
+//Joint C
+tCD=-(14.434+37.818)/2
+FCD=4*tCD  //kN
+tCD=4  //kN
+tCE=-14.434-tCD
+FCE=11.692*4  //kN
+//Joint D
+tDE=-0.5*(-26.126)
+FDE=tDE*4  //kN
+printf("The forces in different members are:-\nAB=%.2d kN\nBC=%.2d kN\nCD=%.2d kN\nDE=%.2d kN\nEA=%.2d kN\nEB=%.2d kN\nEC=%.2d kN",FAB,FBC,FCD,FDE,FAE,FBE,FCE)
+
-- 
cgit