From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3845/CH3/EX3.4/Ex3_4.sce | 18 ++++++++++++++++++ 1 file changed, 18 insertions(+) create mode 100644 3845/CH3/EX3.4/Ex3_4.sce (limited to '3845/CH3/EX3.4/Ex3_4.sce') diff --git a/3845/CH3/EX3.4/Ex3_4.sce b/3845/CH3/EX3.4/Ex3_4.sce new file mode 100644 index 000000000..ff8e119c2 --- /dev/null +++ b/3845/CH3/EX3.4/Ex3_4.sce @@ -0,0 +1,18 @@ +//Example 3.4 +y_0=0;//Initial position (m) +v_y=0;//Final velocity (m/s) +v_0=70;//Initial velocity (m/s) +theta_0=75;//Initial angle (deg) +v_0y=v_0*sind(theta_0);//y-component of initial velocity (m/s) +g=9.8;//Acceleration due to gravity (m/s^2) +y=(v_0y^2-v_y^2)/(2*g)+y_0;//Rearranging Equation 3.45 for maximum height (m) +printf('a.Maximum height = %0.1f m',y) +t=(y-y_0)/(1/2*(v_0y+v_y));//Rearranging Equation 3.37 for time (s) +printf('\nb.Time between launch and explosion of shell = %0.2f s',t) +x_0=0;//Initial horizontal distance (m) +v_x=v_0*cosd(theta_0);//x-component of initial velocity (m/s) +x=x_0+v_x*t;//Rearranging Equation 3.34 for horizontal displacement (m) +printf('\nc.Horizontal displacement of the shell when it explodes = %0.1f m',x) +//Answer varies due to round off error +//Openstax - College Physics +//Download for free at http://cnx.org/content/col11406/latest -- cgit