From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

---
 3835/CH7/EX7.7/Ex7_7.sce | 22 ++++++++++++++++++++++
 1 file changed, 22 insertions(+)
 create mode 100644 3835/CH7/EX7.7/Ex7_7.sce

(limited to '3835/CH7/EX7.7/Ex7_7.sce')

diff --git a/3835/CH7/EX7.7/Ex7_7.sce b/3835/CH7/EX7.7/Ex7_7.sce
new file mode 100644
index 000000000..50e484644
--- /dev/null
+++ b/3835/CH7/EX7.7/Ex7_7.sce
@@ -0,0 +1,22 @@
+clear
+//
+//From the circuit diagram of the figure we can obtain tha following equations based on which the problems are solved
+//eqn 1..........vl=(i1+i2)*zl....the load voltage
+//eqn 2..........vl=e1-i1*z1=e2-i2*z2
+//eqn 3..........i1=(e1-vl)*y1 and i2=(e2-vl)*y2
+//eqn 4..........vl=(e1*y1+e2+y2)/(y1+y2+yl)
+//load voltage case a
+//vl=209.26-j*9.7 in x+iy form and angle is calculated 
+vl=(209.26**2+9.7**2)**0.5
+printf("\n load voltage= %0.5f  v",vl)
+//using eqn 3 the following generator currents are generated
+//i1=7.45-j5.92 for which i1=9.52 at angle -38.45 is generated
+//i2=8.91-j7.17 for which i2=11.43 at angle -38.83 is generated
+//case b
+//the load current il=i1+i2 is obtained as 20.95 at angle -38.65
+printf("\n the load current is 20.95 at angle -38.65")
+//case c
+g1=220*9.52
+g2=220*11.43
+printf("\n The output of generator1= %0.3f  VA",g1)
+printf("\n The output of generator2= %0.4f  VA",g2)
-- 
cgit