From 7bc77cb1ed33745c720952c92b3b2747c5cbf2df Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Sat, 3 Feb 2018 11:01:52 +0530 Subject: Added new code --- 3830/CH6/EX6.1/Ex6_1.sce | 40 ++++++++++++++++++++++++++++++++++++++++ 1 file changed, 40 insertions(+) create mode 100644 3830/CH6/EX6.1/Ex6_1.sce (limited to '3830/CH6/EX6.1/Ex6_1.sce') diff --git a/3830/CH6/EX6.1/Ex6_1.sce b/3830/CH6/EX6.1/Ex6_1.sce new file mode 100644 index 000000000..7a6e42123 --- /dev/null +++ b/3830/CH6/EX6.1/Ex6_1.sce @@ -0,0 +1,40 @@ +// Exa 6.1 + +clc; +clear; + +// Given data + +// Refering bridge shown in fig. 6.8 +R1 = 1000; // Ohms +R2 = 4000; // Ohms +R3 = 100; // Ohms +R4 = 400; // Ohms +Rg = 100; // Ohms +Si = 100; // Sensitivity in mm/microAmp +V = 3; // Voltage applied +R4_imbalance = 1; // resistance added in R4 to create imbalance + +// Solution + +printf('The bridge is originally in balance. Therefore, R1/R3 = R2/R4 \n'); +printf('Let there be imbalance in the bridge circuit because of increase in value of R4 value by 1 Ohm \n'); +printf('Therefore, R4 = 400+X Ohms \n'); +printf('Thevenins Resistance Rth = (100*1000)/(100+1000) + (4000*(400+X))/(4400+X) \n'); // Rth = R1*R3/(R1+R3) + R2*R4/(R2+R4) +printf('Neglecting X \n'); +// Therefore +Rth = R1*R3/(R1+R3) + R2*R4/(R2+R4); +printf('Rth becomes %d ohms \n',round(Rth)); +printf('Eth = [R3/(R1+R3) + R4/(R2+R4)]*E; \n'); +// Applying binomial expansion and neglecting X2 term, X is small +// Therefore +X = R4_imbalance; + +Eth = V*10*X/48400; +printf('Applying binomial expansion, Eth = %.2f µV \n',round(Eth*10^6)); +Ig = Eth/(Rth+Rg); // Galvanometer current +D = Ig*Si; // Deflection in mm +printf('Galvanometer Current Ig = %.3f µA \n', Ig*10^6); +printf('Galvanometer deflection D = %.2f mm \n',D*10^6); + +// The answer provided in the textbook is wrong -- cgit