From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Tue, 10 Oct 2017 12:27:19 +0530
Subject: initial commit / add all books

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 3802/CH3/EX3.10/Ex3_10.sce | 41 +++++++++++++++++++++++++++++++++++++++++
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diff --git a/3802/CH3/EX3.10/Ex3_10.sce b/3802/CH3/EX3.10/Ex3_10.sce
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+//Book Name:Fundamentals of Electrical Engineering
+//Author:Rajendra Prasad
+//Publisher: PHI Learning Private Limited
+//Edition:Third ,2014
+
+//Ex3_10.sce
+
+clc;
+clear;
+//datas are taken from example 3.8
+R=2;   //Resistance in ohm
+L=2;    //Inductor value in henry
+C=1/12;   //capacitor value in farad
+omega=3; //Taken from v(t) value
+//given v(t)=12 sin(3t+30);
+Vm=12;
+Vrms=Vm/sqrt(2);
+theta=30;
+
+Z=complex(R,(omega*L)-(1/(omega*C)));
+V=complex(Vrms*cosd(theta),Vrms*sind(theta));
+I=V/Z; //from Ohm's law
+disp(I,' circuit current is')
+
+Vr=I*R;
+disp(Vr,'Voltage across the resistance is')
+
+theta1=90;
+Xl=complex(omega*L*cosd(theta1),omega*L*sind(theta1));
+Vl=I*Xl;
+disp(Vl,'Voltage across the inductance is')
+
+theta2=-90;
+Xc=complex(cosd(theta2)/(omega*C),sind(theta2)/(omega*C));
+Vc=I*Xc;
+disp(Vc,'Voltage across the capacitance is')
+
+Vsum=Vr+Vl+Vc;
+disp(Vsum,'The sum of three element voltages is')
+
+//Answers are displayed in a complex mode(real and imaginary) because it is solved in  complex method
-- 
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