From d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 Mon Sep 17 00:00:00 2001
From: prashantsinalkar
Date: Sat, 3 Feb 2018 10:59:42 +0530
Subject: Modified the code

---
 3776/CH6/EX6.15/Ex6_15.sce | 14 +++++++-------
 1 file changed, 7 insertions(+), 7 deletions(-)

(limited to '3776/CH6/EX6.15')

diff --git a/3776/CH6/EX6.15/Ex6_15.sce b/3776/CH6/EX6.15/Ex6_15.sce
index ca2df4451..cfbab548a 100644
--- a/3776/CH6/EX6.15/Ex6_15.sce
+++ b/3776/CH6/EX6.15/Ex6_15.sce
@@ -1,12 +1,12 @@
 clear
-//Given 
-//From example 5.8 
-W = 4.0   //N/m - The force distribution 
+//Given
+//From example 5.8
+W = 4.0   //N/m - The force distribution
 L = 3     // m - The length of the force applied
 M = W*L/8.0 // KN.m The moment due to force distribution
-o = 30    // the angle of force applid to horizantal
-l = 150.0 //mm length of the crossection 
-b = 100.0 //mm - width of the crossection 
+o = 30    // the angle of force applied to horizontal
+l = 150.0 //mm length of the crossection
+b = 100.0 //mm - width of the crossection
 //
 M_z = M*(cos(3.14/6))
 M_y = M*(sin(%pi/6))
@@ -14,4 +14,4 @@ I_z = b*(l**3)/12.0
 I_y = l*(b**3)/12.0
 //tanb = I_z /I_y *tan30
 b = atand((I_z*tan(3.14/6.0)/I_y))
-printf("\n The angle at which neutral axis locates is %0.3f degrees",b)
+printf("\n The angle at which neutral axis located by is %0.3f degrees",b)
-- 
cgit