From d1e070fe2d77c8e7f6ba4b0c57b1b42e26349059 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Sat, 3 Feb 2018 10:59:42 +0530 Subject: Modified the code --- 3776/CH12/EX12.10/Ex12_10.sce | 4 ++-- 3776/CH12/EX12.3/Ex12_3.sce | 2 +- 3776/CH12/EX12.5/Ex12_5.sce | 6 +++--- 3 files changed, 6 insertions(+), 6 deletions(-) (limited to '3776/CH12') diff --git a/3776/CH12/EX12.10/Ex12_10.sce b/3776/CH12/EX12.10/Ex12_10.sce index 68fe4e541..31260aee0 100644 --- a/3776/CH12/EX12.10/Ex12_10.sce +++ b/3776/CH12/EX12.10/Ex12_10.sce @@ -1,7 +1,7 @@ clear //Given -A_1 = 0.125 //in2 , The area of the crossection of AB -A_2 = 0.219 //in2 , The area of the crossection of BC +A_1 = 0.125 //sq.in , The area of the crossection of AB +A_2 = 0.219 //sq.in , The area of the crossection of BC l_1 = 3*(5**0.5) //in , The length of AB l_2 = 6*(2**0.5) //in , The length of BC p = 3 //k , Force acting on the system diff --git a/3776/CH12/EX12.3/Ex12_3.sce b/3776/CH12/EX12.3/Ex12_3.sce index f99a26393..889a51fee 100644 --- a/3776/CH12/EX12.3/Ex12_3.sce +++ b/3776/CH12/EX12.3/Ex12_3.sce @@ -11,7 +11,7 @@ l_ab = 2.5 //mt - The length of the rod l_bc = 2 //mt - The length of the rod A_ab = 5*(10**-4) //mt2 the areaof ab A_bc = 5*(10**-3) //mt2 the areaof bc -E = 70 //Gpa The youngs modulus of the material +E = 70 //GPa The youngs modulus of the material e_a =(p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E))*(10**-6) //KN-m //Part -2 due to flexure I = 60*10**6 //mm4 - the moment of inertia diff --git a/3776/CH12/EX12.5/Ex12_5.sce b/3776/CH12/EX12.5/Ex12_5.sce index c7bb91a72..cd3e6dbc7 100644 --- a/3776/CH12/EX12.5/Ex12_5.sce +++ b/3776/CH12/EX12.5/Ex12_5.sce @@ -7,8 +7,8 @@ F_ab = 2500 //lb F_bc = -2500 //lb l_ab = 60 //in - The length of the rod l_bc = 60 //in - The length of the rod -A_ab = 0.15 //in2 the areaof ab -A_bc = 0.25 //in2 the areaof bc +A_ab = 0.15 //sq.in the areaof ab +A_bc = 0.25 //sq.in the areaof bc E = 30*(10**6) //psi The youngs modulus of the material //Part_a e_a =p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E) //lb-in the deflection @@ -16,7 +16,7 @@ e_a =p_ab*l_ab*F_ab/(A_ab*E) + p_bc*l_bc*F_bc/(A_bc*E) //lb-in the deflection p_bd = 1 //lb The recorded virtual loading F_bd = 1 //lb l_bd = 40 //in - The length of the rod -A_bd = 0.1 //in2 the areaof ab +A_bd = 0.1 //sq.in the areaof ab e_a_1 =p_ab*p_ab*l_ab/(A_ab*E) + p_bc*p_bc*l_bc/(A_bc*E) +p_bd*p_bd*l_bd/(A_bd*E) //lb-in the deflection //Since the produced defelection should compensate the other one x_d = e_a/e_a_1 -- cgit