From 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 Mon Sep 17 00:00:00 2001 From: prashantsinalkar Date: Tue, 10 Oct 2017 12:27:19 +0530 Subject: initial commit / add all books --- 3751/CH7/EX7.4/Ex7_4.sce | 26 ++++++++++++++++++++++++++ 1 file changed, 26 insertions(+) create mode 100644 3751/CH7/EX7.4/Ex7_4.sce (limited to '3751/CH7/EX7.4/Ex7_4.sce') diff --git a/3751/CH7/EX7.4/Ex7_4.sce b/3751/CH7/EX7.4/Ex7_4.sce new file mode 100644 index 000000000..bbfd9ddbc --- /dev/null +++ b/3751/CH7/EX7.4/Ex7_4.sce @@ -0,0 +1,26 @@ +//Fluid Systems by Shiv Kumar +//Chapter 7 - Performance of water turbine +//Example 7.4 +//To Find (a) The Diameter of Runner (b) The Diameter of jet + clc + clear +//Given: + P=3200; //Power Developed, kW + H=310; // Effective Head , m + eta_o=82/100; //Overall Efficiency + Ku=0.46; // Speed Ratio + Cv=0.98 // Co-efficient of Velocity + Ns=18; //Specific Speed (SI Units) +//Data required + rho=1000; //Density of Water, Kg/m^3 + g=9.81 // Acceleration due to gravity, m/s^2 + +//Computations + N=Ns*H^(5/4)/sqrt(P); //Speed, rpm + D=Ku*sqrt(2*g*H)*60/(%pi*N); //Diameter of runner, m + Q=P*1000/(rho*g*H*eta_o); //Discharge, m^3/s + d=sqrt(Q/((%pi/4)*Cv*sqrt(2*g*H))); // Diameter of Jet, m + +//Results + printf("(a) The Diameter of Runner, D =%.2f m\n",D) //The Answer Vary due to Round Off Error + printf("(c) The Diameter of Jet, d=%.3f m \n",d) -- cgit